Bidder | Amount | Date |
---|---|---|
g****o 203 | USD 400.00 | 03/23/2019 11:54:12 |
C****n 14 | USD 385.00 | 03/23/2019 11:54:12 |
g****o 203 | USD 370.00 | 03/23/2019 11:42:38 |
Y****e 7 | USD 355.00 | 03/23/2019 11:36:12 |
C****n 14 | USD 350.00 | 03/23/2019 11:36:12 |
C****n 14 | USD 340.00 | 03/23/2019 11:14:00 |
g****o 203 | USD 325.00 | 03/23/2019 11:14:00 |
g****o 203 | USD 315.00 | 03/23/2019 10:57:47 |
Y****e 7 | USD 300.00 | 03/23/2019 10:57:16 |
g****o 203 | USD 285.00 | 03/23/2019 10:57:16 |
Y****e 7 | USD 265.00 | 03/23/2019 01:34:48 |
g****o 203 | USD 250.00 | 03/23/2019 01:34:32 |
Y****e 7 | USD 250.00 | 03/23/2019 01:34:32 |
g****o 203 | USD 230.00 | 03/22/2019 17:50:38 |
T****a 5 | USD 220.00 | 03/17/2019 13:55:10 |
g****o 203 | USD 210.00 | 03/17/2019 13:38:06 |
T****a 5 | USD 200.00 | 03/17/2019 13:00:00 |
C****n 14 | USD 180.00 | 03/17/2019 12:54:46 |
T****a 5 | USD 160.00 | 03/17/2019 12:53:07 |
T****a 5 | USD 150.00 | 03/17/2019 12:02:24 |
Cubicdissection.com description: "The Binary Burr is a classic Bill Cutler design. It was awarded a First Prize at the 2003 IPP Puzzle Design Competition, and has been unavailable for several years. Here is what Bill has to say about it:
"The Binary Burr is a burr that functions like a 6-ring version of the Chinese Rings. The puzzle consists of 21 pieces. One is equivalent to the ‘bar’ in a Chinese Rings puzzle, and six others are equivalent to the ‘rings’. The other 14 pieces in the puzzle construct a ‘cage’ or ‘box’ that holds the other pieces in place. The entire puzzle should perhaps be called a ‘boxed burr’, and might be more logically constructed with only a solid wooden cage, however Bill chose to dissect this outer shell into smaller burr-like pieces.
To disassemble the puzzle, the rings and bar must be manipulated until the bar is freed. After the bar is removed, then the rings can be removed one-at-a-time, and finally the remaining pieces come apart easily.
The number of moves required to remove the first piece is 85, which is approximately 2 * (2/3) * 2^6 or 85.3 . Each move of a ring on or off the bar in the Binary Burr requires two moves - a movement of the bar piece, and a movement of the ring piece"